Question

Решите методом замены системы уравнений:​

Answer 1

$left { {{2frac{1}{3}x-frac{1}{9}y=4} atop {1.6x-frac{1}{30}y=3}} right. Longrightarrow left { {{2frac{1}{3}x-frac{1}{9}y=4} atop {1.6x=3+frac{1}{30}y}} right. Longrightarrow left { {{2frac{1}{3}x-frac{1}{9}y=4} atop {x=1.875+frac{1}{48}y}} right. \\\\2frac{1}{3}(1.875+frac{1}{48}y)-frac{1}{9}y=4\\4.375+frac{7}{144}y-frac{1}{9}y=4\\4.375-frac{1}{16}y=4\\y=6\\\\x=1.875+frac{1}{48}*6\\x=1.875+0.125\\x=2$

Ответ: х=2; у=6