Question

Помогите найти произвольную функции

Answer 1

Ответ:

7) y' = 1/(2*sin(1-2*x)^(1/2))*(-2)*cos(1-2*x)

8) y' = 3 * (-1) * (5x^3 + 4*x)^(-2) * (15*x^2 + 4)

9) y' = (3*x^2 * sin(x) - cos(x) * x^3) / sin(x)^2

Пошаговое объяснение:

7) y = (sin(1-2*x)^(1/2)

y' = 1/(2*sin(1-2*x)^(1/2))*(-2)*cos(1-2*x)

8) y = 3/(5*x^3 + 4*x) = 3 * (5*x^3 + 4*x)^(-1)

y' = 3 * (-1) * (5x^3 + 4*x)^(-2) * (15*x^2 + 4)

9) y = x^3/sin(x)

y' = (3*x^2 * sin(x) - cos(x) * x^3) / sin(x)^2

Answer 2

спасибо)))