Question

y=asqrt(2)Lnt
y'=?
y''=?
y'''=?

Answer 1

Ответ:

Пошаговое объяснение:

y=a(√2)t

y'(x)=y''(x)=y'''(x)=0

y'(t)=a(√2)/t; y''(t)=- a(√2)/t²;  y'''(t)=2a(√2)/t³

y'(a)=(√2)t; y''(t)=y'''(t)=0

Answer 2

y=a√2Lnt

Answer 3

y'=(a√2)/t

Answer 4

y"=_(a√2)/t

Answer 5

y'''=(a√2)/2

Answer 6

(1/t)'=-1/t² !