Question

6.92 (2,4) ставлю 50 баллов

Answer 1

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Готово!!!Удачи)))))

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Answer 2

Задание 2 :

$1)frac{2m+1}{2m-1}-frac{2m-1}{2m+1}=frac{4m^{2}+4m+1-(4m^{2}-4m+1)}{(2m-1)(2m+1)}=frac{4m^{2}+4m+1-4m^{2}+4m-1}{(4m^{2}-1 }=frac{8m}{4m^{2}-1 }\\2)frac{8m}{4m^{2}-1 }:frac{4m}{10m-5}=frac{8m}{(2m-1)(2m+1)}*frac{5(2m-1)}{4m}=frac{10}{2m+1}$

Задание 4 :

$1)frac{x^{2} }{y^{2} }+frac{y}{x}=frac{x^{3}+y^{3}}{xy^{2} }\\2)frac{x}{y^{2} }-frac{1}{y}+frac{1}{x}=frac{x^{2}-xy+y^{2}}{xy^{2} }\\3)frac{x^{3}+y^{3}}{xy^{2}}:frac{x^{2}-xy+y^{2}}{xy^{2} }=frac{(x+y)(x^{2}-xy+y^{2})}{xy^{2} }*frac{xy^{2} }{x^{2}-xy+y^{2}} =x+y$