Question

y²-6y+9 : 10y-30
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y²-9 y²+3y при y=70
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Answer 1

$frac{y^2-6y+9}{y^2-9}:frac{10y-30}{y^2+3y}=frac{(y-3)^2}{(y-3)(y+3)}cdotfrac{y(y+3)}{10(y-3)}=frac{y}{10}\\frac{y}{10}=frac{70}{10}=7$

Ответ: 7