Question

Решите пожалуйста систему уравнения ​

Answer 1

$begin{cases} frac{15x-3y}{4}+frac{3x+2y}{6}=3 / *12 \frac{3x+y}{3}-frac{x-3y}{2}=6 /*6 end{cases}\\ begin{cases} 3(15x-3y)+2(3x+2y )=36 \2(3x+y)-3( x-3y) =36end{cases}\\begin{cases} 45x-9y +6x+4y =36 \6x+2y -3x+9y=36end{cases}\\begin{cases}51x-5y =36 \3x+11y=36 /*(-17)end{cases}\\begin{cases}51x-5y =36 \-51x-187y=-612end{cases}\+----------\-192y=-576 /:(-192)$

$y=3\\3x+11y=36\3x+11*3=36\3x+33=36\3x=36-33\3x= 3 /:3\x=1\\begin{cases} x=1 \y=3 end{cases}$