Question

помогите, пожалуйста​

Answer 1

$begin{cases}x+y=-6\xy=-16 end{cases}\\begin{cases} y=-x-6\x (-x-6)+16=0 end{cases} \\begin{cases} y=-x-6\ -x^2-6x+16=0 end{cases}\\-x^2-6x+16=0 /*(-1)\x^2+6x-16=0\\D=b^2-4ac=6^2-4*1*(-16)=36+64=100$

$x_{1}=frac{-b-sqrt{D}}{2a}=frac{-6-sqrt{100}}{2*1}=frac{-6-10}{2 }=frac{-16}{2}=-8\\x_{2}=frac{-b+sqrt{D}}{2a}=frac{-6+sqrt{100}}{2*1}=frac{-6+10}{2 }=frac{4}{2}=2\\begin{cases} x=-8 \ y=-x-6 end{cases} vee begin{cases} x=2 \ y=-x-6 end{cases}\\begin{cases} x=-8 \ y=8-6 end{cases} vee begin{cases} x=2 \ y=-2-6 end{cases}\\begin{cases} x=-8 \ y=2 end{cases} vee begin{cases} x=2 \ y=-8 end{cases}$