Question

Помогите решить пожалуйста
(см.прикреплённое фото)​

Answer 1

$left ( frac{m^2-5m+25}{25m^2-1}*frac{5m^2+m}{m^3+125}-frac{m+5}{5m^2-m} right ):frac{5}{m^2+5m}-frac{25m+22}{5-25m}=\\\=left ( frac{ m^2-5m+25 }{ (5m -1)(5m+1)}*frac {m (5m + 1)}{m^3+ 5^3}-frac{m+5}{m(5m -1)} right ):frac{5} {(m +5)m}-frac{25m+22}{5(1- 5m)}=\\\ = left ( frac{ m^2-5m+25 }{ 5m -1 }*frac {m }{(m + 5)(m^2-5m+25) }-frac{m+5}{m(5m -1)} right ):frac{5} {(m +5)m}-frac{25m+22}{5(1- 5m)}=$

$=left ( frac{ 1 }{ 5m -1 }*frac {m }{ m + 5 }-frac{m+5}{m( 5m-1)} right )*frac {(m +5)m}{5}+frac{25m+22}{5( 5m-1)}= \\\= left ( frac {m }{( 5m -1) (m + 5) }-frac{m+5}{m(5m -1)} right )*frac {(m +5)m}{5}-frac{25m+22}{5( 1-5m )}= \\\=left ( frac {m *m -(m+5) (m+5)}{ m (5m -1) (m + 5) } right )*frac {(m +5)m}{5}+frac{25m+22}{5( 5m-1)}= \\\= left ( frac {m *m - (m^2+5m+5m+25 }{ m (5m -1) (m + 5) } right )*frac {(m +5)m}{5}+frac{25m+22}{5( 5m-1)}=$

$= left ( frac {m^2- m^2-5m-5m-25 }{ m (5m -1) (m + 5) } right )*frac {(m +5)m}{5}-frac{25m+22}{5( 1-5m )}= \\\=left ( frac {-10m -25 }{ 5m -1 } right )*frac {1}{5}-frac{25m+22}{5( 1-5m )}= left ( frac {-5(2m+5) }{ 5m -1 } right )*frac {1}{5} -frac{25m+22}{5( 1-5m )}= \\\= frac { 2m+5 }{ 1-5m } -frac{25m+22}{5( 1-5m )}= frac { 5(2m+5)-25-22 }{ 5(1-5m )}= frac { 10m+25-25m-22 }{ 5(1-5m )}=\\\= frac { 3-15m }{ 5(1-5m )} = frac { 3(1- 5m) }{ 5(1-5m )}=frac{3}{5}$

Answer 2

спасибо большое

Answer 3

:)