Question

Сократить дробь а)x^3+x/x^2; б)x^2+3*y/y^2-9

Answer 1

a)

$frac{x^3+x}{x^2} =frac{x(x^2+1)}{x*x} \left { {{frac{x^2+1}{x} } atop {xneq 0}} right.$

б)

$frac{y^2+3y}{y^2-9} =frac{y(y+3)}{(y+3)(y-3)} \left { {{frac{y}{y-3} } atop {yneq -3}} right.$