Question

y=kx+b A(7;3),B(-2;4). Решите

Answer 1

$k = frac{y2 - y1}{x2 - x1} = frac{4 - 3}{ - 2 - 7} = - frac{1}{9} \k = frac{y - y1}{x - x1} = frac{y - 3}{x - 7} = - frac{1}{9} \ 9y - 27 = - x + 7 \ 9y = - x + 7 + 27 \ 9y = - x + 34 \ y = - frac{1}{9} x + frac{34}{9} \ y = - frac{1}{9} x + 3 frac{7}{9}$