Question

Добрый вечер! Помогите решить :)

Answer 1

$displaystylemathbf{int{sqrt{x}+sqrt[3]{x^4}over x}mathrm{dx}=int(x^{-{1over2}}+x^{1over3})mathrm{dx}={x^{-{1over2}+1}over -{1over2}+1}+{x^{{1over3}+1}over {1over3}+1}+C=2sqrt{x}+{3over4}sqrt[3]{x^4}+C}$