Question

2×7^log7x=x2-3 спростити вираз

Answer 1

$2*7^{log_7X}=x^2-3\a^{log_ab}=b\2*x=x^2-3\x^2-2x-3=0\D^2= (-2)^2-4*(-3)=4+12=16, D=+-4\x_1=frac{2+4}{2}=3\x_2=frac{2-4}{2}=-1\(x-3)(x+1)=0$