Question

Разложите на множители квадратный трёхчлен:
1)x^2+3x-40
2)6x^2+x-12

Answer 1

$x {}^{2} + 3x - 40 = x {}^{2} + 8x - 5x - 40 = (x + 8)(x - 5)$

$6x {}^{2} + x - 12 = 6x {}^{2} + 9x - 8x - 12 = (2x + 3)(3x - 4)$

Answer 2

1)x^2+3x-40=х^2+8х-5х-40=х(х+8)-5(х+8)= (х+8)(х-5)

2)6x^2+x-12 =6х^2+9х-8х-12=3х(2х+3)-4(2х+3)=(2х+3)(3х-4)