Question

решите пожалуйста срочно!!!!!!!​

Answer 1

▪1.

$a) : : : {(3a + b)}^{2} = 9 {a}^{2} + 6ab + {b}^{2} \ \ b) : : : (y - frac{1}{5}x )(y + frac{1}{5}x ) = {y}^{2} - frac{1}{25} {x}^{2}$

▪2.

$a) : : : {m}^{2} - 81 {n}^{2} = (m - 9n)(m + 9n) \ \ б) : : : 25 + 10p + {p}^{2} = {(5 + p)}^{2} \ \ в) : : : 6 {b }^{7} - 24 : {b} ^{4} = 6 {b}^{4} ( {b}^{3} - 4)$

▪3.

$( {17.6}^{2} - {2.4}^{2} ) div 10 = (17.6 - 2.4)(17.6 + 2.4) div 10 = 15.2 times 20 div 10 = 15.2 times 2 = 30.4$

▪4.

$y(7x - y) + {(x - y)}^{2} = 7xy - {y}^{2} + {x}^{2} - 2xy + {y}^{2} = 5xy + {x}^{2} = x(5y + x) \ \ - 1 times (5 times 0.2 + ( - 1)) = - (1 - 1) = 0$

▪5.

$a) : : : 20 {m}^{2} - 5 {n}^{4} = 5(4 {m}^{2} - {( {n}^{2}) }^{2} ) = 5(2m - {n}^{2} )(2m + {n}^{2} ) \ \ b) : : : 64 {c}^{3} - {b}^{3} = (4c - b)(16 {c}^{2} + 4bc + {b}^{2} )$

▪6.

${(x + 1)}^{2} = 36 \ {x}^{2} + 2x + 1 - 36 = 0 \ {x}^{2} + 2x - 35 = 0 \ d = 4 - 4 times ( - 35) = 4 + 140 = 144 \ x_{1} = frac{ - 2 + sqrt{144} }{2} = frac{ - 2 + 12}{2} = frac{10}{2} = 5 \ x_{2} = frac{ - 2 - sqrt{144} }{2} = frac{ - 2 - 12}{2} = frac{ - 14}{2} = - 7$