Question

помогите срочно! 2cos2a+3sin2a/5cos2a-sin2a

Answer 1

$frac{2cos, 2a+3sin2a}{5cos2a-sin2a}=[, frac{:, cos2a}{:, cos2a}; ]=frac{2+3tg2a}{5-tg2a}=frac{3cdot (tg2a+frac{2}{3})}{-(tg2a-5)}=-3cdot frac{tg2a-5+5+frac{2}{3}}{tg2a-5}=\\=-3cdot Big (1+frac{17}{3(tg2a-5)}Big )=-3-frac{17}{tg2a-5}$