Question

Найдите tg150° * sin150°.​

Answer 1

$tg150^circ cdot sin150^circ =tg(180^circ -30^circ )cdot sin(180^circ -30^circ )=\\=-tg30^circ cdot sin30^circ =-frac{sqrt3}{3}cdot frac{1}{2}=-frac{sqrt3}{6}$