Question

Помогите решить уравнения ДАЮ 45 баллов
1) 3,4*(5х-0,16)=0,476

2)128:(2,4х+19,04)=6,4

3)4,4:х:0,3=0,26

4)11,2:y+0,32=0,6

5)(x+9,14):7,2=5

Answer 1

$displaystylett 1)\ 3,4(5x-0,16)=0,476\5x-0,16=0,476:3,4\5x-0,16=0,14\5x=0,14+0,16\5x=0,3\x=0,3:5\x=0,06\\ 2)\ 128:(2,4x+19,04) = 6,4\2,4x + 19,04 = 128 : 6,4\2,4x + 19,04 = 20\2,4x = 20 - 19,04\ 2,4x = 0,96\ x = 0,96 : 2,4\x = 0,4$

$displaystylett3)\4,4:x:0,3=0,26\\ frac{44}{10}cdotfrac{1}{x}cdotfrac{10}{3}=frac{26}{100}\\ frac{44}{3x}=frac{13}{50}; xneq0\\ 3xcdot13=44cdot50\\ 39x=2200\\x=frac{2200}{39}=56frac{16}{39}$

$displaystylett 4)\ 11,2:y+0,32=0,6\ 11,2:y=0,6-0,32\11,2:y=0,28\ y=11,2:0,28\y=40\\ 5)\ (x+9,14):7,2=5\x+9,14=5cdot7,2\x+9,14=36\x=36-9,14\x=26,86$