Question

Решите уравнение (х+у-1)²+(2х-у-8)²=0

Answer 1

${(x + y - 1)}^{2} = - {(2x - y - 8)}^{2} \ \ x + y - 1 = 0 \ 2x - y - 8 = 0 \ \ y = 1 - x \ y = 2x - 8 \ \ 1 - x = 2x - 8 \ x = 3 \ y = 1 - 3 = - 2$

Ответ: (3;-2)