Question

Решите пожалуйста даю 75 баллов

Answer 1

1)

$5 - 2x = 3(10 + x) \ 5 - 2x - 30 - 3x = 0 \ - 25 - 5x = 0 \ - 5x = 25 \ x = - 5$

2)

$sqrt{x + 3} (5x - 6) = 0 \ sqrt{x + 3} = 0 \ 5x - 6 = 0 \ x + 3 = 0 \ 5x = 6 \ x = - 3 \ x = frac{6}{5} \ - 3 + frac{6}{5} = - 1.8$

3)

$3 {x}^{2} - 13x + 12 = 0 \ d = 169 - 4 times 3 times 12 = 169 - 144 = 25 \ x = frac{13 + 5}{6} = 3 \ x2 = frac{4}{3} \ frac{4}{3} times 3 = 4$

4)

$3(x - 2) - 2 > 4 - x \ 3x - 6 - 4 + x > 0 \ 4x - 10 > 0 \ x > frac{10}{4}$

5)

$2x - 5 < 0 \ 7x + 28 > 0 \ x < frac{5}{2} \ x > - 4$

Ответ 2

6)

${x}^{2} + 3x - 10 leqslant 0 \ x {}^{2} + 3x - 10 = 0 \ x1 = - 5 \ x2 = 2$

Ответ [-5;2]

Ответ 8