Question

x^2-4x-3x√x^2-4x+20=0​

Answer 1

Ответ:

x1 ≈ -5.7

x2 ≈ 1.7

Объяснение:

x^2-4x-3x√x^2-4x+20=0​

x^2-4x-3x^2-4x+20=0​

-2x^2-8x+20=0​

2x^2+8x*-20=0​

x^2+4x*-10=0​

Д = 16-4*(-10)=56

x1 = -4 - √56/2·1 = -2 - √14 ≈ -5.7

x2 = -4 + √56/2·1 = -2 + √14 ≈ 1.7