Question

ПОМОГИТЕ ПОЖАЛУЙСТА ДАМ 34 БАЛОВ

Answer 1

$1); ; (x+4)(x-6)geq 0; ,qquad +++[-4]---[, 6, ]+++\\xin (-infty ,-4, ]cup ], 6,+infty )\\2); ; -x^2+3,5x+2geq 0; |cdot (-2); ; to ; ; 2x^2-7x-4leq 0\\D=81; ,; x_1=-frac{1}{2}; ; ,; ; x-2=4\\(x+frac{1}{2})(x-4)geq 0qquad +++[-frac{1}{2}, ]---[;, 4, ]+++\\xin (-infty ,-frac{1}{2}, ]cup [, 4,+infty )\\Otvet:; ; -1; ,; 2in (-infty ,-frac{1}{2}, ]cup [, 4,+infty ); .\\3); ; -x^2+9x-14>0; |cdot (-1); ; to ; ; x^2-9x+14<0\\D=25; ,; ; x_1=2; ,; x_2=7$

$+++(2)---(7)+++\\xin (2,7); ; Rightarrow ; ; celue; x:; ; x=3,4,5,6; .\\4); ; left { {{x^2-3x-4>0} atop {3x+12>0}} right.; left { {{(x+4)(x-1)>0} atop {3(x+4)>0}} right. ; left { {{xin (-infty ,-4)cup (1,+infty )} atop {xin (-4,+infty )}} right. ; ; Rightarrow ; ; xin (1,+infty )\\5); ; frac{4+4x+x^2}{6-5x+x^2}>0; ; ,; ; frac{(x+2)^2}{-(x-1)(x+6)}>0; ; ,; ; frac{(x+2)^2}{(x-1)(x+6)}<0\\+++(-6)---(0)---(1)+++\\xin (-6,0)cup (0,1)$

$6); ; y=sqrt{x-3}+sqrt{x^2-7x+6}\\OOF:; ; left { {{x-3geq 0} atop {x^2-7x+6geq 0}} right. ; left { {{xgeq 3qquad quad } atop {(x-1)(x-6)geq 0}} right.; left { {{y=2} atop {x=2}} right. left { {{xgeq 3} atop {xin (-infty ,-6)cup (-1,+infty )}} right. \\xin [, 3,+infty )$