Question

(6х7-2х5+10)'
$(4 sqrt{ times )} .$
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Answer 1

$3); ; (4x^7-2x^5+19)'=6cdot (x^7)'-2cdot (x^5)'+10'=\\=6cdot 7x^6-2cdot 5x^4+0=42x^6-10x^4\\\4); ; Big (frac{5}{x^5}Big )'=-frac{5cdot (x^5)'}{(x^5)^2}=-frac{25x^4}{x^{10}}=-frac{25}{x^6}\\ili; ; ; Big (frac{5}{x^5}Big )'=(5x^{-5})'=5cdot (-5)x^{-6}=-frac{25}{x^6}$