Question

решите неравенство (25 б)​

Answer 1

$(frac{1}{5})^{x-1} +(frac{1}{5})^{x+1} leq26\\(frac{1}{5})^{x-1}*(1+(frac{1}{5})^{2})leq26\\(frac{1}{5})^{x-1}*(1+frac{1}{25})leq26\\(frac{1}{5})^{x-1}*frac{26}{25}leq26\\(frac{1}{5})^{x-1}leq25\\5^{1-x}leq5^{2}\\1-xleq2\\-xleq1\\xgeq -1\\xin[-1;+infty)$