Question

помогите решить уровнения Даю 40баллов!
х2 – 12х = 0
4х3 –х = 0
(3х + 1)(8 – 0,5х) = 0
9х2 – 6х = -1

Answer 1

1.х(х-12)=0

х=0;х=12

2.х(4х^2-1)=0

х=0 ; 4х^2-1=0

4х^2=1

х^2=+-0,5

Answer 2

1)

${x}^{2} - 12x = 0 \ x(x - 12) = 0 \ x1 = 0 \ x2 = 12$

2)

$4{x}^{3} - x = 0 \ x = 4 {x}^{3 } \ x = 0$

3)

$(3x + 1)(8 - 0.5x) = 0 \ x1 = - frac{1}{3} \ x2 = 16$

Доказательство:

$- frac{1}{3} times 3 + 1 = - 1 + 1 = 0$

$8 - 0.5 times 16 = 8 - 8 = 0$

4)

$9 {x}^{2} - 6x = - 1 \ 9 {x}^{2} - 6x + 1 = 0 \ d = { ( - 6)}^{2} - 4 times 9 times 1 = 36 - 36 = 0 \ x1.2 = frac{6 - 0}{2 times 9} = frac{1}{3}$