Question

Решите уравнение (х-3)^2-3х=(х-3)(3+х)

Answer 1

$(x - 3) ^{2} - 3x = (x - 3)(3 + x)$

$(x - 3)(x - 3) - 3x = (x - 3)(3 + x)$

${x}^{2} - 6x + 9 - 3x = 3x + {x}^{2} - 9 - 3x$

$- 9x = - 9 - 9$

$- 9x = - 18$

$x = frac{ - 19}{ - 8} = 2$

Ответ :

$2$

Answer 2

x^2-6x+9-3x=3x+x^2-9-3x

x^2-9x+9=x+x^2-9

x^2-9x+9-x-x^2+9=0

-10x+18=0

-10x=-18

x=1,8