Question

Решить уравнение.
а) 2sinx+3sinx-5=0 б) sin2x-cosx=0

Answer 1

а) 2sinx + 3sinx - 5 = 0

5sinx = 5

sinx = 1

x = π/2 + 2πk ; k € Z

б) sin2x - cosx = 0

2sinx cosx - cosx = 0

cosx(2sinx - 1) = 0

cosx = 0 2sinx = 1

x = π/2 + πn, n € Z sinx = 1/2

x = π/6 + 2πk

x = 5π/6 + 2πk, k € Z