Question

памагите решить задание

Answer 1

1.

$sqrt{8} = sqrt{2 times 4} = 2 sqrt{2}$

$sqrt{12} = sqrt{3 times 4} = 2 sqrt{3}$

$sqrt{48} = sqrt{16 times 3} = 4 sqrt{3}$

$sqrt{200} = sqrt{25 times 4 times 2} = 5 times 2 times sqrt{2} = 10 sqrt{2}$

2.

$sqrt{50 } - sqrt{18} + sqrt{72} = sqrt{25 times 2} - sqrt{9 times 2} + sqrt{36 times 2} = 5 sqrt{2} - 3 sqrt{2} + 6 sqrt{2} = 8 sqrt{2}$

3.

$5 sqrt{3} < 4 sqrt{5} \ 5 sqrt{3} = sqrt{ {5}^{2} times 3 } = sqrt{25 times 3} = sqrt{75} \ 4 sqrt{5} = sqrt{ {4}^{2} times 5 } = sqrt{16 times 5} = sqrt{80} \ sqrt{75} < sqrt{80}$

Answer 2

спасиьо

Answer 3

спасибо

Answer 4

обращайся

Answer 5

Ответ:

Объяснение:

1)

√8= 2√2

√12= 2√3

√48= 4√3

√200= 10√2

2) 5√2-3√2+6√2= 8√2

0,3*4√2+1/3*3√2=1,2√2+√2= 2,2√2

3) √75 и √80

75<80

значит 5√3<4√5