Question

Решите вариант 5.10 класс. Даю 40 баллов

Answer 1

$1)lim_{-3 }( frac{1}{3} {x}^{2} - 2x + 1 ) = \ = frac{1}{3} times 9 + 6 + 1 = 10 \ 2)lim_{3} frac{ {x}^{2} + x - 12}{x - 3} = \ = lim_{3} frac{ (x - 3)(x + 4)}{x - 3} = 7 \ 3) lim_{ infty } frac{ 2{n}^{2} + 9}{ {n}^{2} + n - 8 } = \ = lim_{ infty } frac{ 2 + frac{9}{ {n}^{2} } }{ 1 + frac{1}{n} - frac{8}{ {n}^{2} } } = 2 \ 4)lim_{ infty } frac{ 3x + 5}{x} = \ =lim_{ infty }( 3 + frac{5}{x} ) = 3$