Question

sin(3п/2+a)/ctg(2п-a) * tg(п/2+a)/sin(п+a)

Answer 1

sin(3π/2+α)/ctg(2π-α) * tg(π/2+α)/sin(π+α)=-cosα/(-ctgα)*(-ctgα)/(-sinα)=

-sinα*(-ctgα)/-sinα=-ctgα

Answer 2

+ctg

Answer 3

опечатка.

Answer 4

Решение задания приложено