Question

Lim(x^2+2) х стремится к 2
Lim x ->2 x^2-4/x-2
Lim x-> бесконечности 5х-3+х^2 / 2-3х^+х

Answer 1

$limlimits_{x to 2}(x^2+2)=2^2+2=6\\\limlimits _{x to 2}; frac{x^2-4}{x-2}=limlimits _{x to 2}frac{(x-2)(x+2)}{x-2}=limlimits _{x to 2}; (x+2)=2+2=4\\\limlimits _{x to infty}frac{5x-3+x^2}{2-3x^2+x}=limlimits _{x to infty}frac{x^2}{-3x^2}=-frac{1}{3}$