Question

Помогите решить третье задание

Answer 1

Ответ:

y = -1;х = 2.

$left { {{2x+2y=2} atop {3^{x-y} =27}} right.\3^{3}=27\left { {{2(x+y)=2} atop {x-y=3}}} right.\left {{{x+y=1} atop{x-y=3}} right.\left { {{y=1-x} atop {x-(1-x)=3}} right.\left { {{y=1-x} atop {x-1+x=3}} right.\left { {{y=1-x} atop {2x=4}} right.\left { {{y=1-x} atop {x=2}} right.\left { {{y=1-2=-1} atop {x=2}} right.$