Question

найдите производную функции h(x)=lnx-4x2

Answer 1

$h(x)=lnx-4x^2\\y'=(lnx)'-4cdot (x^2)'=frac{1}{x}-4cdot 2x=frac{1}{x}-8x$

Answer 2

h'(x)=(lnx-4x²)'=1/x-8x