Question

cos 3x=2 под корнем /2

Answer 1

$cos 3x=frac{sqrt{2} }{2}$

$3x=бarccosfrac{sqrt{2} }{2}+2pi n,$ $n$ ∈ $Z$

$3x=бfrac{pi }{4} +2pi n,$ $n$ ∈$Z$

$x=бfrac{pi }{12} +frac{2pi n}{3} ,$ $n$ ∈ $Z$