Question

Log4 8+log4 4-log4 16

Answer 1

$log_48+log_44-log_416=log_4(8cdot4)-log_416=log_432-log_416=\ \ =log_4frac{32}{16}=log_42=log_{2^2}2=frac{1}{2}log_22=frac{1}{2}$