Question

Помогите с Уравнениями! Дам 30 баллов

Answer 1

12

$(4\frac{1}{2}-2x)*3\frac{2}{3}=\frac{11}{15}\\4\frac{1}{2}-2x=\frac{11}{15} : 3\frac{2}{3}\\4\frac{1}{2}-2x=\frac{11}{15} : \frac{11}{3}\\4\frac{1}{2}-2x=\frac{11}{15} * \frac{3}{11}\\4\frac{1}{2}-2x=\frac{1}{5} \\4.5-2x=0.2\\-2x=-4.3\\x=\frac{4.3}{2}=\frac{43}{20}\\x=2.15$

13

$3\frac{1}{3}:2\frac{2}{9}=12\frac{1}{5}:x\\ \frac{10}{3}:\frac{20}{9}=12\frac{1}{5}:x\\\frac{10}{3}*\frac{9}{20}=12\frac{1}{5}:x\\\frac{3}{2} =12\frac{1}{5}:x\\1.5=12.2:x\\12.2:x=1.5\\x=12.2:1.5\\x=\frac{12.2}{1.5}=\frac{122}{15}\\x=8\frac{2}{15}$

14

$2\frac{3}{8}:3\frac{1}{6}=9\frac{1}{10}:x\\\frac{19}{8}:\frac{19}{6}=9\frac{1}{10}:x\\\frac{19}{8}*\frac{6}{19}=9\frac{1}{10}:x\\\frac{3}{4}= 9\frac{1}{10}:x\\0.75=9.1:x\\9.1:x=0.75\\x=\frac{9.1}{0.75}=\frac{910}{75}=\frac{182}{15}\\x=12\frac{2}{15}$