Question

Помогите с решением!!!!!!

Answer 1

Ответ:

8       ...............................................

Объяснение:

Answer 2

Ответ: 8.

Решение:

$(\sqrt[5]{5^{x+3}})^x^-^1 = 25^{x+1} \\\\(5^{\frac{x+3}{5}})^x^-^1 = (5^{2})^x^-^1 \\\\5^{\frac{x^2+2x-3}{5}} = 5^{2x-2}\\\\\frac{x^2+2x-3}{5} = 2x-2\\\\5(2x-2)=x^2+2x-3\\\\10x - 10 = x^2+2x-3\\\\x^2-8x-13=0\\\\D = (-8)^2-4*1*(-13) = 64-52=12\\\\x_{1} =\frac{-(-8)+\sqrt{12}}{2*1} = 4+\sqrt{3} \\\\x_{2} = \frac{-(-8)-\sqrt{12}}{2} = 4-\sqrt{3}\\\\x_{1}+x_{2} = (4+\sqrt{3})+(4-\sqrt{3}) = 8.$