Question

решить уравнение кореньх+1=2х-8​

Answer 1

$\sqrt{x + 1} = 2x - 8 \\ { \sqrt{x + 1} }^{2} = {(2x - 8)}^{2} \\ x + 1 = 4 {x}^{2} - 32x + 64 \\ 4 {x}^{2} - 33x + 63 = 0 \\ d = 990 + 99 - 252 \times 4 = 1089 - 1008 = 81 = {9}^{2} \\ x = \frac{33 + - 9}{8} \\ x1 = \frac{42}{8} = 5.25 \\ x2 = 3$

ОДЗ: х>=-1