Question

решите рожалуйста
(10¹²+5¹¹×2⁹-5¹³×2⁸)÷(4×5⁵×10⁶)​

Answer 1

$\displaystyle\tt \frac{10^{12}+5^{11}\cdot2^9-5^{13}\cdot2^8}{4\cdot5^5\cdot10^6}= \frac{(2\cdot5)^{12}+5^{11}\cdot2^9-5^{13}\cdot2^8}{2^2 \cdot5^5\cdot(5\cdot2)^6}=\\\\\\= \frac{2^{12}\cdot5^{12}+5^{11}\cdot2^9-5^{13}\cdot2^8}{2^2\cdot5^5\cdot5^6\cdot2^6}= \frac{2^{8}\cdot5^{11}(2^4\cdot5+2-5^{2})}{2^8\cdot5^{11}}=\\\\\\=16\cdot5+2-25=57$

Answer 2

Ответ:

= (10¹² + 10⁹ ·5² - 10⁸· 5⁵) : (4·5⁵·10⁶) = 10⁸(10⁴ + 10·5² - 5⁵) : 10⁸·5³ = (2⁴·5⁴ + 2·5³ - 5⁵) : 5³ = 5³ (2⁴·5 + 2 - 5²) : 5³ = 16·5 + 2 - 25 = 80 - 25 +2 = 57

Объяснение: