Question

AC=4
Угол А=60°
Угол В=45°
ВС=?

Answer 1

По т синусов:

$\frac{AC}{sinB} =\frac{AB}{sinC} =\frac{BC}{sinA} \\\frac{AC}{sinB} =\frac{BC}{sinA} \\BC=\frac{AC*sinA}{sinB} =\frac{4*\frac{\sqrt{3} }{2} }{\frac{\sqrt{2} }{2} } =2\sqrt{6}$