Question

Ре­ши­те урав­не­ние

Answer 1

$x^{2} =2x+8\\\\x^{2}-2x-8=0\\\\D=(-2)^{2}-4*(-8)=4+32=36=6^{2}\\\\x_{1}=\frac{2+6}{2}=4\\\\x_{2}=\frac{2-6}{2}=-2\\\\Otvet:-2;4$