Question

13 баллов помогите!​

Answer 1

а) $\sqrt{m^2-2m+1} =\sqrt{(m-1)^2} =|m-1|=1-m\ npu\ m\leq 1$

б) $\sqrt{9m^2-6m+1} =\sqrt{(3m-1)^2} =|3m-1|=1-3m\ npu\ m<\frac{1}{3}$

в) $\sqrt{y^2-10y+25}+\sqrt{y^2-14y+49}=\sqrt{(y-5)^2}+\sqrt{(y-7)^2}=$

  $=|y-5|+|y-7|=y-5+y-7=2y-12\ npu\ y\geq 7$

г) $\sqrt{z^2-4z+4}+\sqrt{z^2+8z+16}=\sqrt{(z-2)^2}+\sqrt{(z+4)^2}=$

  $=|z-2|+|z+4|=2-z+z+4=6\ npu\ -4\leq z\leq 2$