Question

решите систему уравнений​

Answer 1

$\left \{ {{x-y=1,} \atop {\frac{x}{2}+\frac{y}{4}=\frac{2x-y}{3} |\cdot12; }} \right. \Leftrightarrow \left \{ {{x=y+1,} \atop {6(y+1)+3y=4(2(y+1)-y). (*)}} \right.$

$(*): 6(y+1)+3y=4(2(y+1)-y),\\6y+6+3y=4(2y+2-y),\\9y+6=4y+8,\\5y=2 |:5,\\y=0,4.$

$\left \{ {{x=y+1,} \atop {6(y+1)+3y=6(2(y+1)-y);}} \right. \Leftrightarrow \left \{ {{y=0,4,} \atop {x=0,4+1;}} \right. \Leftrightarrow \left \{ {{x=1,4,} \atop {y=0,4.}} \right.$

Ответ: (1,4; 0,4).