Question

10 баллов. решите пожалуйста буду очень благодарен​

Answer 1

$7) -16x^2 + 16x - 4 = 0 => 4x^2 - 4x + 1 = 0 => (2x-1)^2 = 0 => 2x-1 = 0 => x = 0.5\\Answer: 0.5\\8) x^2-16x-1 = 5x(x-4) => x^2 - 16x-1=5x^2-20x => 4x^2-4x+1=0 =>(2x-1)^2=0 =>2x-1=0 => x = 0.5\\Answer: 0.5\\9)(2y-3)(5y+1)=2y+0.4 => 10y^2-13y-3 = 2y+0.4=>10y^2-15y-3.4=0\\D = 225 + 40*3.4 = 19^2 => y_1_2 = \frac{15(+-)19}{20}\\Answer: y_1=-0.2\\y_2=1.7\\10) (2x-3)^2-77 = x+5 => 4x^2-12x+9-77=x+5 => 4x^2-13x-73=0\\D = 169 + 16*73 = 1337 => x_1_2 = \frac{13(+-)\sqrt{1337}}{8}$$Answer: \frac{13(+-)\sqrt{1337}}{8}$

Answer 2

Ответ:

Пошаговое объяснение:

7.

4x² - 4x + 1 = 0

(2x - 1)² = 0

x = 0,5

8.

x² - 16x - 1 = 5x² - 20x

4x² - 4x + 1 = 0

(2x - 1)² = 0

x = 0,5

9.

10y² - 15y + 2y - 3 = 2y + 0,4

10y² - 15y - 3,4 = 0

D = 225 + 136 = 361 = 19²

x1 = (15 - 19)/20 = -0,2

x2 = (15 + 19)/20 = 1,7

10.

4x² - 12x + 9 - 77 = x + 5

4x² - 13x - 73 = 0

D = 169 + 1168 = 1337

x1 = (13 - √1337)/8

x2 = (13 + √1337)/8