Question

Решите пожалуста C1 с обеих вариантов​

Answer 1

$x^2 = |x|^2\\C1.1\\3x^2 + \frac{x^2}{|x|}-4 = 0\\3x^2 + |x| - 4 = 0\\3|x|^2+|x|-4 = 0\\|x| = t \geq 0\\3t^2 + t - 4 = 0\\t_1 = 1 => |x| = 1 => x_1 = 1; x_2 = -1\\t_2 = -\frac{4}{3}<0\\Answer: x_1 = 1; x_2 = -1\\C1.2\\x^2 + \frac{x^2}{|x|}-6 = 0\\|x|^2 + |x| - 6 = 0\\|x| = t \geq 0\\t^2 + t - 6 = 0\\t_1 = 2 => |x| = 2 => x_1=2;x_2=-2\\t_2 = -3 < 0\\Answer: x_1 = 2; x_2=-2$