Question

x(x^2+2x+1) =6(x+1)​

Answer 1

x(x² + 2x + 1) = 6(x + 1)

x(x + 1)² - 6(x + 1) = 0

(x + 1)[x(x + 1) - 6] = 0

(x + 1)(x² + x - 6) = 0

(x + 1)(x + 3)(x - 2) = 0

$\left[\begin{array}{ccc}x+1=0\\x+3=0\\x-2=0\end{array}\right\\\\\left[\begin{array}{ccc}x_{1}=-1 \\x_{2}=-3 \\x_{3}=2\end{array}\right\\\\Otvet:\boxed{-3;-1;2}$