Question

Очень прошу вашей помощи по математике!!!

Answer 1

$y = x^{e^{cos(x)}}\\ln(y) = e^{cos(x)}ln(x)\\\frac{y'}{y} = -sin(x)e^{cos(x)}ln(x) + \frac{e^{cos(x)}}{x}\\y' = ye^{cos(x)}(\frac{1}{x} - ln(x)sin(x))\\y' = x^{e^{cos(x)}}e^{cos(x)}(\frac{1}{x} - ln(x)sin(x)) =x^{(e^{cos(x)}-1)}e^{cos(x)}(1 - xln(x)sin(x))\\Answer: y' = x^{(e^{cos(x)}-1)}e^{cos(x)}(1 - xln(x)sin(x))$