Question

(2а + 3)² =
(5+4b)(4b-5)
3x³-48x=0
50x-2x³=0​

Answer 1

Ответ:

$(5+4b)(4b-5) = 16b^{2} - 25$

${(2a + 3)}^{2} = 4a ^{2} + 12a + 9$

$3x^{3} - 48x = 0 \\ 3x( {x}^{2} - 16) = 0 \\ 3x = 0 \\ x = 0 \\ {x}^{2} - 16 = 0 \\ {x}^{2} = 16 \\ x = 4 \\ x = - 4$

$50x-2x^3=0$

$2x(25-2x^2)=0$

$2x=0 или 25-2х^2=0$

x=0 или х=√12,5 или х= -√12,5