Question

Помогите пж! Срочно!

Answer 1

a) 2x + 5 > 7x - 10

2x - 7x > - 10 - 5

- 5x > - 15

x < 3

Ответ : x ∈ (- ∞ ; 3)

б) 2(3x + 7) - 8(x + 3) ≤ 0

6x + 14 - 8x + 24 ≤ 0

- 2x ≤ - 38

x ≥ 19

Ответ : x ∈ [19 ; + ∞)

в)

$\frac{x}{7}-6\geq  x\\\\\frac{x}{7}*7-6*7\geq x*7\\\\x-42\geq 7x\\\\x-7x\geq 42\\\\-6x\geq 42\\\\x\leq -7\\\\Otvet:\boxed{x\in(-\infty;-7]}$

$\left \{ {{3(x-4)-4(x+3)\leq0} \atop {3x+2(3x-2)>5}} \right.\\\\\left \{ {{3x-12-4x-12\leq0} \atop {3x+6x-4>5}} \right.\\\\\left \{ {{-x\leq24 } \atop {9x>9}} \right.\\\\\left \{ {{x\geq-24} \atop {x>1}} \right.\\\\Otvet:\boxed{x\in(1;+\infty)}$