Question

Устраните разрыв. y=3x^2+2x-5\3x+5

Answer 1

$y = \frac{3 {x}^{2} + 2x - 5 }{3x + 5}$
$0 = \frac{3 {x}^{2} + 2x - 5 }{3x + 5}$
$0 = \frac{3 {x}^{2} + 5x - 3x - 5 }{3x + 5}$
$0 = \frac{x(3x + 5) - (3x + 5)}{3x + 5}$
$0 = \frac{(3x + 5) \times (x - 1)}{3x + 5}$
$0 = x - 1$
$- x = - 1$
$x = 1$