Question

1) -3x+2=-8x+7+5x
2) 5-3(x+7)=8x+(-6x-8)
3) (9x-2)(3x+27)=0
4) 5-(6x-2)=7x+(-3x+1)
5) x(x+25)=0

Прошу решите, все заранее большая благодарность ! :)

Answer 1

Ответ:

1) -3x + 2 = -8x + 7 + 5x

-3х + 8х - 5х = 7 - 2

0х = 5

Ответ: ∅

2) 5 - 3(x + 7) = 8x - 6x - 8

5 - 3x - 21 = 2x - 8

-3x - 2x = -8 - 5 +21

-5x = 8

x = -1,6

3) (9x - 2)(3x + 27) = 0

27x² + 243x - 6x - 54 = 0

27x² + 237x - 54 = 0

D = 56169 + 5832 = 62001

$\sqrt{D} = 249$

$x_1 = \frac{-237 - 249}{54} = -\frac{486}{54} = -9$

$x_1 = \frac{-237 + 249}{54} = \frac{12}{54} = \frac{2}{9}$

4) 5 - (6x - 2) = 7x + (-3x + 1)

5 - 6x + 2 - 7x + 3x - 1 = 0

-10x + 6 = 0

-10x = -6

x = 0,6

5)  x(x + 25)=0

x₁ = 0

x₂ = -25